Move makedict to LatinIME android keyboard.

Bug: 6188977
Change-Id: I4d2ef504bb983abbda3cb52ee450cb46f58d95cf

1 files changed, 72 insertions, 0 deletions

diff --git a/java/src/com/android/inputmethod/latin/makedict/Word.java b/java/src/com/android/inputmethod/latin/makedict/Word.java
new file mode 100644
index 000000000..c2c01e1f8
--- /dev/null
+++ b/java/src/com/android/inputmethod/latin/makedict/Word.java
@@ -0,0 +1,72 @@
+/*
+ * Copyright (C) 2011 The Android Open Source Project
+ *
+ * Licensed under the Apache License, Version 2.0 (the "License"); you may not
+ * use this file except in compliance with the License. You may obtain a copy of
+ * the License at
+ *
+ * http://www.apache.org/licenses/LICENSE-2.0
+ *
+ * Unless required by applicable law or agreed to in writing, software
+ * distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
+ * WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
+ * License for the specific language governing permissions and limitations under
+ * the License.
+ */
+
+package com.android.inputmethod.latin.makedict;
+
+import com.android.inputmethod.latin.makedict.FusionDictionary.WeightedString;
+
+import java.util.ArrayList;
+
+/**
+ * Utility class for a word with a frequency.
+ *
+ * This is chiefly used to iterate a dictionary.
+ */
+public class Word implements Comparable<Word> {
+    final String mWord;
+    final int mFrequency;
+    final boolean mIsShortcutOnly;
+    final ArrayList<WeightedString> mShortcutTargets;
+    final ArrayList<WeightedString> mBigrams;
+
+    public Word(final String word, final int frequency,
+            final ArrayList<WeightedString> shortcutTargets,
+            final ArrayList<WeightedString> bigrams, final boolean isShortcutOnly) {
+        mWord = word;
+        mFrequency = frequency;
+        mShortcutTargets = shortcutTargets;
+        mBigrams = bigrams;
+        mIsShortcutOnly = isShortcutOnly;
+    }
+
+    /**
+     * Three-way comparison.
+     *
+     * A Word x is greater than a word y if x has a higher frequency. If they have the same
+     * frequency, they are sorted in lexicographic order.
+     */
+    @Override
+    public int compareTo(Word w) {
+        if (mFrequency < w.mFrequency) return 1;
+        if (mFrequency > w.mFrequency) return -1;
+        return mWord.compareTo(w.mWord);
+    }
+
+    /**
+     * Equality test.
+     *
+     * Words are equal if they have the same frequency, the same spellings, and the same
+     * attributes.
+     */
+    @Override
+    public boolean equals(Object o) {
+        if (!(o instanceof Word)) return false;
+        Word w = (Word)o;
+        return mFrequency == w.mFrequency && mWord.equals(w.mWord)
+                && mShortcutTargets.equals(w.mShortcutTargets)
+                && mBigrams.equals(w.mBigrams);
+    }
+}